The only addition I have is to adapt the code to create a single INSERT query in the format I gave earlier. It will run quicker overall.
---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/ > -----Original Message----- > From: Charles Kline [mailto:[EMAIL PROTECTED] > Sent: Saturday, March 29, 2003 9:11 PM > To: Peter Lovatt > Cc: [EMAIL PROTECTED] > Subject: Re: [PHP-DB] INSERT Question > > Big help! Thanks much. > > Now... to figure out how to create that kind of form in HTML_QuickForm > (hehehe). If I can't then I just make it by hand, but now I know the > method! Phew... always more to learn. > > - Charles > > > On Saturday, March 29, 2003, at 08:51 PM, Peter Lovatt wrote: > > > Hi > > > > you need to create 5 selects, all named investigator[] with index 1-5 > > (or > > 0-4), with the option set to empty for no selection. > > > > this will return an array > > investigator[1] => '1064618047' > > investigator_yesno[1] => 'Y' > > > > investigator[2] => '1649815377' > > investigator_yesno[2] => 'N' > > > > for example > > > > > > <form> > > <table> > > <tr> > > <td> > > <select name="investigator[1]"> > > <option value="">Choose person</option> > > <option value="1064618047">Paul A</option> > > <option value="1655387822">Katrina A</option> > > <option value="1649815377">David A</option> > > </select> > > is a primary investigator? > > <input name="investigator_yesno[1]" value="Y" type="radio" > > checked="checked" />Yes > > <input name="investigator_yesno[1]" value="N" type="radio" />No > > </td> > > </tr> > > <tr> > > <td> > > <select name="investigator[2]"> > > <option value="">Choose person</option> > > <option value="1064618047">Paul A</option> > > <option value="1655387822">Katrina A</option> > > <option value="1649815377">David A</option> > > </select> > > is a primary investigator? > > <input name="investigator_yesno[2]" value="Y" type="radio" > > checked="checked" />Yes > > <input name="investigator_yesno[2]" value="N" type="radio" />No > > </td> > > </tr> > > ...more here .... > > </table> > > </form> > > > > > > > > on the script receiving the data you then need a for loop to insert > > the > > records, one for each person > > > > > > for ($i = 1; $i <= 4; $i++) > > { > > //only do it if there is a value for $investigator[$i], ie there is a > > selection > > if($investigator[$i]) { > > $query = 'INSERT INTO tbl_report_people > > (record_id > > , person_id > > , investigator_yesno > > ) > > VALUES > > ("'.$record_id[$i].'" > > , "'.$investigator[$i].'" > > , "'.$investigator_yesno[$i].'" > > ) > > '; > > $mysql_result = mysql_query($query, $mysql_link); > > > > }//end if > > > > }//end for > > > > > > > > hope this helps > > > > Peter > > > > > > > > > > > > > > > > -- > > PHP Database Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
