Hi All,
Solved my problem!
Here's the code in case anyone really cares :P
$col = explode(",",$threadsColumn);
$col_search = "(";
for ($i=0;$i<count($col);$i++) {
$col_search .= $col[$i]." LIKE
'%$threadsName%'";
if ($i != (count($col) - 1)) {
$col_search .= " OR ";
}
}
$col_search .= ")";
Thanks again Adam for your spelling error notice!
Aaron
-----Original Message-----
From: Adam Voigt [mailto:[EMAIL PROTECTED]
Sent: June 26, 2003 10:26 AM
To: Aaron Wolski
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] moving though an array..
One Thing:
Change $columns[] to $colums, example:
$columns = explode(',',$threadsColumn);
On Thu, 2003-06-26 at 10:23, Aaron Wolski wrote:
> Hi All,
>
> Hopefully someone here can point me in the right direction.
>
> I need to create a SELECT statement based on some criteria select and
> entered into a form.
>
> Form variables:
>
> $threadsColumn = "manufactuer,colour";
> $string = "n";
>
> Code:
>
> $columns[] = explode(",",$threadsColumn);
>
> $test = "(";
>
> for ($i=0;$i<sizeof($columns);$i++) {
>
> $test .= $columns[$i]." %$string%";
>
> }
>
> $test .= ")";
>
> echo $test;
>
> What I am attempting to do is create a select statement that would
look
> like (based on "form variables"):
>
> SELECT * FROM tablename WHERE (manufacturer LIKE %n% OR colour LIKE
%n%)
>
> The information between ( and ) needs to be written in such a manner
> that it scales up or down in options.. depending on what was selected
in
> the form.
>
> ANYONE have some thoughts?
>
> Oh.. when I echo the above code I get this: (Array %h%)
>
> Thanks!
>
> Aaron
>
--
Adam Voigt ([EMAIL PROTECTED])
Linux/Unix Network Administrator
The Cryptocomm Group
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