Hello,
Does anyone know what would cause this message?
Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result
resource in c:\program files\easyphp\www\bod-rse\bod\menu.php3 on line 49...
Here is the code:
<?
$command = "SELECT * FROM central_fakepaths WHERE menu != '0' ORDER BY menu
ASC";
$result = mysql_query("$command",$mysqlHandle);
$path_directory=explode("/", $HTTP_SERVER_VARS["REQUEST_URI"]);
while ($myrow = mysql_fetch_row($result))
{
$count++;
If ($path_directory[1]=="$devsite") { $path = $myrow[9]; $target =
$myrow[10]; }
else { $path = $myrow[7]; $target =
$myrow[3]; }
If ($myrow[5] != $count)
{ echo "<img src=\"images/menu-line.gif\" width=\"139\"
height=\"7\"><br>\n";
$count++;
}
// IF MENU VALUE == COMMITTEES
if ($myrow[2] == "Committees")
{
echo "<font face=Verdana size=1><img src='images/menu-line.gif'
width=139 height=7><BR>
<a href='.' target='_top'>Committees</a><BR>
<img src='images/menu-line.gif' width=139 height=7><BR>";
$currdate = date("Y-m",time());
$cdate = explode("-" , $currdate);
$cyear = $cdate[0];
$cmonth = $cdate[1];
if ($cmonth >=7 AND $cmonth <=12) $fyear = $cyear + 1;
else $fyear = $cyear;
$fyear2 = $fyear - 1;
$syear = "$fyear2 - $fyear";
$commandw = "SELECT menuname, type, active, name FROM bod_board_boards
WHERE type='committee' AND active='1' ORDER BY name ASC";
$resultw = mysql_query("$commandw",$mysqlHandle);
while ($myroww = mysql_fetch_row($resultw))
{
if ($myroww[0] !="")
{
echo " <a href='committees.php?bord=$bord&comm=$myroww[3]'
target='_top'>$myroww[0]</a><BR>";
}
}
//echo " <a href='?bord=$bord' target='_top'>What They Do</a>";
}
else
{
echo " <a href='$path' target='$target'>$myrow[2]</a><br>\n";
}
}
?>
Any help would be unendingly appreciated...
Keith
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