Do you have an 'or die(mysql_error())'  statement following your
mysql_query($result) line.  99% of the time, this error means your query
failed.  if it works on another server....are the fields the same, the
dbname, the tablename?

hth
jeff


                                                                                       
                                                 
                      "Greg Hetrick"                                                   
                                                 
                      <[EMAIL PROTECTED]        To:       [EMAIL PROTECTED]            
                                               
                      net>                     cc:                                     
                                                 
                                               Subject:  [PHP-DB] mysql_fetch_array 
issues.                                             
                      07/09/2003 12:04                                                 
                                                 
                      PM                                                               
                                                 
                                                                                       
                                                 
                                                                                       
                                                 




I am getting the following error when attempting to pull data out of a
mysql
DB

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in /home/pffl/public_html/pffl/webpage/html/dataentry.php on line
125

I can take this same code to a different web server and it is pulling
correctly!

I am currently running Apache 2.0.46 with PHP 4.3.2 I was running Apache
1.3.x with PHP 4.3.1 and getting the same thing, any ideas? here is the
chunk of code where I use the function.

while ($myrow=mysql_fetch_array($result))
        {
                ?>
                <option value="<?print $myrow['name'];?>, <?print
$myrow['team'];?>"> <? echo $myrow["name"]; ?></option>
                <?
        }

Any Ideas.



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