I'd worry about the empty dates after. and use something like.
$qry = "select date1, date2 from table";
$result = mysql_query($qry) or die(mysql_error());
while ($rs = mysql_fetch_row($result)) {
//this array could be built a number of ways, one is
$bookdate[] = array($rs[0],$rs[1]);
}
if i've not misunderstood, that should work
hth
jeff
mike karthauser
<[EMAIL PROTECTED] To: <[EMAIL PROTECTED]>
m.co.uk> cc:
Subject: [PHP-DB] Populating an array
from mysql db
08/28/2003 08:01
AM
I have a course booking system that allows the client to add courses and
then specify how long they run for. The admin system I have built allows
the
client to add up to 30 dates for each instance of the course and these are
adding to a database row in the form date1, date2, date3, daten etc.
What I am trying to achieve now is to extract this data into an array so I
can count how many dates have been added and to display the dates.
If the course runs for eg. 2 days - values of date1 and date2 would be
populated as date1=2003-09-01, date2=2003-09-02 - all other dates would be
default to 0000-00-00 and I wish to ignore these.
I'm trying to work out how to set up a loop to extract positive dates from
my db so I end up with
$bookdate[0] = '2003-09-01';
$bookdate[1] = '2003-09-02'; etc
Can anyone provide me with some help in this extraction?
Thanks in advance.
--
Mike Karthauser
Managing Director - Brightstorm Ltd
Email >> [EMAIL PROTECTED]
Web >> http://www.brightstorm.co.uk
Tel >> 0117 9426653 (office)
07939 252144 (mobile)
Snailmail >> Unit 8, 14 King Square,
Bristol BS2 8JJ
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