thanx Mike for your help!!
appreciatively,
hh
----- Original Message -----
From: "Ford, Mike [LSS]" <[EMAIL PROTECTED]>
To: "'Ng Hwee Hwee'" <[EMAIL PROTECTED]>; "DBList" <[EMAIL PROTECTED]>
Sent: Thursday, December 18, 2003 6:06 PM
Subject: RE: [PHP-DB] Search Query
> On 18 December 2003 05:26, Ng Hwee Hwee wrote:
>
> > Dear all,
> >
> > i need help with my search query statement.. what is wrong
> > with my code?
>
> Nothing obvious that I can see, except a little inefficiency. Where do
> $keyword and $table come from? -- is this a register_globals issue?
>
>
> > <snip>
> > $word = split(" ", $keyword);
> > $num_words = count($word);
> > $word_str = "";
> > $criteria = "";
> >
> > for ($i=0; $i<$num_words; $i++)
> > {
> > if ($i)
> > $word_str .= "and colName like '%".$word[$i]."%' ";
> > else $word_str .= "colName like '%".$word[$i]."%' ";
> > }
> > $word_str .= "and col2 = '$foo' ";
> >
> > $criteria .= "$word_str ";
>
> I'd replace all of the above with:
>
> $criteria = "colName like '%"
> . str_replace(' '
> , "%' and colName like '%"
> , $keyword)
> . "%'"
> . " and col2 = '$foo' "
>
> > $table .= "db_table";
> >
> > $query = "select * from ".$table." where ".$criteria; </snip>
> >
> > when i try to echo $query, i get --- select * from where
> >
> > and so of course MySQL gives me an error 1064 near ' where '
> >
> > what happened?
>
> What's your error_reporting level? HAve you tried cranking it up to E_ALL
> to see if any relevant warnings are being generated that you're not
> currently seeing?
>
> Cheers!
>
> Mike
>
> ---------------------------------------------------------------------
> Mike Ford, Electronic Information Services Adviser,
> Learning Support Services, Learning & Information Services,
> JG125, James Graham Building, Leeds Metropolitan University,
> Beckett Park, LEEDS, LS6 3QS, United Kingdom
> Email: [EMAIL PROTECTED]
> Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
>
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