I think this is what you want:

SELECT *
FROM Locations L, Brick B
WHERE (LEFT(L.'Post Code',3) = LEFT(B.Brick,3))

If you want to select 4 characters change the 3 to 4 :-)

Avoid using spaces and special characters in your column it may give you
problems.


----- Original Message -----
From: "Shaun" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, February 17, 2004 10:04 AM
Subject: Re: [PHP-DB] Brick Codes


> Thanks for your reply,
>
> but what I actually need to do is compare the first 3 or 4 digits of the
> postcode stored in locations to the same in the Brick table...
>
>
> "Ricardo Lopes" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
> > That may depend of what database server you are using, for mysql you can
> > use:
> >
> > ........   WHERE (LEFT('Brick',3) = LEFT(Post Code,3))
> >
> > If you are using other dbserver, check your manual.
> >
> > ----- Original Message -----
> > From: "Shaun" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Monday, February 16, 2004 10:45 PM
> > Subject: [PHP-DB] Brick Codes
> >
> >
> > > Hi,
> > >
> > > I have a table of Locations around the country. My system produces
> reports
> > > based on these Locations. I also have a table containing Brick Codes
> e.g.
> > >
> > > Brick    Post Code
> > > AB51    AB51
> > > AB52    AB52
> > > AB55    AB55
> > > AB56    AB56
> > > AL01    AL1
> > > AL02    AL2
> > > AL03    AL3
> > > AL04    AL4
> > >
> > >
> > > How can I compare the first 3 or 4 letters of the postcode in the
> > Locations
> > > table to the corresponding entry in the Brick Codes table so I can add
> it
> > to
> > > my report?
> > >
> > > Thanks for your help
> > >
> > > --
> > > PHP Database Mailing List (http://www.php.net/)
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> > >
> > >
>
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