RE: [PHP-DB] Php if statement in a form (solved)

[Justin.Baiocchi]

Not to worry - manage to solve the problem using the line below

$date=date('H:i');
echo "<input name=\"timeout\" type=\"text\" value=\"$date\">";

Thanks for all the input


-----Original Message-----
From: Baiocchi, Justin (CSIRO IT, Armidale) 
Sent: Friday, 6 August 2004 12:50 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Php if statement in a form


Well, this works: so you were all on the right track

if($row['timeout']=="")
    {
    print "<input name='timeout' type='text' value='"echo
date('H:i')"'>";
    }else{
    print $row["timeout"];
    }

But now I get a parse error on the <input> line


-----Original Message-----
From: Ng Hwee Hwee [mailto:[EMAIL PROTECTED] 
Sent: Friday, 6 August 2004 12:30 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Php if statement in a form


what about this?

if(empty($row["timeout"]))


----- Original Message ----- 
From: "Doug Thompson" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Friday, August 06, 2004 10:18 AM
Subject: Re: [PHP-DB] Php if statement in a form


> if (is_null($row["timeout"]).....)
> 
> [EMAIL PROTECTED] wrote:
> > Still no joy. The parse error actually refers to the --  if
> > ($row["timeout"] IS NULL); --- line.
> > 
> >

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