The following script:
<html>
<head><title>Share the fun!</title></head>
<style type="text/css">
<!--
body {
font: normal 10px verdana;
background: #ffcccc url("arc.gif") 120px 70px no-repeat;
}
input {
border: 1px solid #ff9966;
text-align:right;
}
u {
color: #ff3333;
}
-->
</style>
<body>
<p> </p>
<p> </p>
<center>
<?php
if ($v = strtolower($_POST['email'])) {
$host = mysql ;
$user = "myusername" ;
$pass= "mypassword" ;
mysql_connect($host , $user , $pass ) ;
mysql_select_db("ng") ;
$sql = "SELECT * FROM arcadia WHERE email=$v";
$res = mysql_query( $sql ) ;
if (list($row) = mysql_fetch_array($res)) {
echo "<b>Your email: <u>$v</u> already in the list<br>";
}
else {
$sql_in = "INSERT INTO arcadia ('email') VALUES ('$v')";
$result_in = mysql_query($sql_in);
echo "<b>Your email: <u>$v</u> subscribed!<br>";
}
}
else {
header("location : http://ng.clawz.com/index.php";);
exit;
}
?>
</center>
</body>
</html>
gives the error:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in /var/www/ng/subscribe.php on line 32
the concept of the script is to first see if the subscribed email is not
already in the list (to prevent double subscription) before subscribing. but
dis always come out wit d above error. what do you think could be wrong?
---------------------------------
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www.opeyemi.tk
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