try this


<?php for ($r=0;$products = db_fetch($productsQuery);$r++) { if (($r % 2) == 0) { echo "</tr> <tr valign=\"top\">"; }

echo "<td align=\"center\">
<a href=".$base_url."products/".$category."/".$products['name_url']
class="product_link"><img src=".$base_url."product_images/thumbs/".$products['thumb'] border="0"
width=\"159\"><br>".$products['name']."</a></td>";


}
?>



bastien



From: "Aaron Wolski" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Subject: [PHP-DB] How to get 2 columns to display
Date: Mon, 6 Dec 2004 08:43:21 -0500

Hi guys,

I'm trying to get two columns of <td></td> to display side by side and
then go to a new row. I am using this code but nothing I seem to do is
working this far.

<?php
for ($r=0;$products = db_fetch($productsQuery);$r++)
{
?>
      <td align="center"><a href="<?php echo $base_url; ?>products/<?php
echo $category; ?>/<?php echo $products['name_url']; ?>"
class="product_link"><img src="<?php echo $base_url;
?>product_images/thumbs/<?php echo $products['thumb']; ?>" border="0"
width="159"><br><?php echo $products['name']; ?></a></td>
<?php
 if ((($r+1) % 2) == 0)
 {
?>
    </tr>
    <tr valign="top">
<?php
 }
}
?>

What is happening with this code is I am getting results like:

<tr>
        <td>IMAGE HERE</td>
        <td>IMAGE HERE</td>
        <td>IMAGE HERE</td>
        <td>IMAGE HERE</td>
        <td>IMAGE HERE</td>
</tr>

What I WANT is:

<tr>
        <td>IMAGE HERE</td>
        <td>IMAGE HERE</td>
</tr>
        <td>IMAGE HERE</td>
        <td>IMAGE HERE</td>
</tr>
        <td>IMAGE HERE</td>
        <td></td>
</tr>

ANY clue where I am going wrong?

Thanks so much.

Aaron

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