Unlike ASP, $result1 is a handle to the dataset, not the data set itself. You need to access the data first and then incorporate that into your query like this:

$l = 2;
$result1 = ("SELECT * FROM Drivers WHERE League = $l");

$row = mysql_fetch_array($result1);
$driverID = $row['DriverID'];


$result2 = mysql_query("SELECT DriverID, Driver, CarNbr FROM Drivers LEFT JOIN $LeagueList ON Drivers.DriverID = $driverID WHERE $driverID) Is Null ORDER BY Drivers.DriverID");


hth

Bastien




From: "Pete Ruby" <[EMAIL PROTECTED]>
Reply-To: "Pete Ruby" <[EMAIL PROTECTED]>
To: php-db@lists.php.net
Subject: [PHP-DB] MySQL - Query within a query
Date: Wed, 16 Mar 2005 00:03:19 -0500

I am looking to do the following w/ MySQL and PHP.  Have 1 query that gets
results, then use those results in another query:

$l = 2;
$result1 = ("SELECT * FROM Drivers WHERE League = $l");

$result2 = mysql_query("SELECT DriverID, Driver, CarNbr FROM Drivers LEFT
JOIN $LeagueList ON Drivers.DriverID = $Result1.DriverID
   WHERE $Result1.DriverID) Is Null ORDER BY Drivers.DriverID");

I can do it w/ Access and MSSQL, but if I try in MySQL, i get an error, both
in DBManager (MySQL interface), and in PHP.


Any help is appreciated.  Thanx!

Pete

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