I made that modification and now it doesn't update the DB at all... Here is the code that I am using to insert that variable into my MySQL DB... Again, my variable is defined as $rec2day = date("Y-m-d") OR $rec2day = date("Y/m/d")
<?php $connection = @mysql_connect("$server", "$user", "$pass") or die("Couldn't Connect To Server."); $db = @mysql_select_db($dbname, $connection) or die("Couldn't Select Database."); $sql = "UPDATE $table1 SET last_access_date=$rec2day WHERE username='$dealer_number' AND password='$password'"; $result = @mysql_query($sql,$connection) or die("Couldn't Execute Query."); ?> "Bruno Ferreira" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Chase wrote: > >>I have a variable: >> $rec2day = date("Y-m-d"); >>that displays correctly when echoed to the screen, but when I write it to >>my DB, I get the mathmatical answer to the equasion (1989 (2005-06-10)). >> >>What do I need to do to correct this?? >> > Just use $rec2day= date("Y/m/d"); > > You database system doesn't like using "-" as a separator in dates, > thus thinking it's a minus sign and doing the appropriate math. Just use > slashes and you'll probably be OK. > > -- Bruno Ferreira > --- > [This E-mail scanned for viruses by Declude Virus] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php