Oops - sorry, got that one completely wrong! A solution should say:
form code:
define("JOVIAL", "likes to joke alot");
define("CHEERFUL", "always wears a smile on his face");
define("ADVENTUROUS", "likes sports and plays well too");
define("MYSTERIOUS", "there's always something to discover everyday");
<select name="myType">
<option value="JOVIAL"><?=JOVIAL;?></option>
<option value="CHEERFUL"><?=CHEERFUL;?></option>
<option value="ADVENTUROUS"><?=ADVENTUROUS;?></option>
<option value="MYSTERIOUS"><?=MYSTERIOUS;?></option>
</select>
form handling code:
$Type = array();
$Type["JOVIAL"]=JOVIAL;
$Type["CHEERFUL"]=CHEERFUL;
$Type["ADVENTUROUS"]=ADVENTUROUS;
$Type["MYSTERIOUS"]=MYSTERIOUS;
echo "You selected" $Type[$myType];
Hope I got it right this time...
Arno
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-----Original Message-----
From: Ng Hwee Hwee [mailto:[EMAIL PROTECTED]
Sent: 13 October 2005 08:13
To: PHP DB List
Subject: [PHP-DB] Defined Constants
Hi all,
just a very simple question. my form has the following define statements and
select box:
define("JOVIAL", "likes to joke alot");
define("CHEERFUL", "always wears a smile on his face");
define("ADVENTUROUS", "likes sports and plays well too");
define("MYSTERIOUS", "there's always something to discover everyday");
<select name="myType">
<option value="JOVIAL"><?=JOVIAL;?></option>
<option value="CHEERFUL"><?=CHEERFUL;?></option>
<option value="ADVENTUROUS"><?=ADVENTUROUS;?></option>
<option value="MYSTERIOUS"><?=MYSTERIOUS;?></option>
</select>
after i post my form, the value $myType will be one of my define statements.
For example, user chooses "CHEERFUL" thus when i echo $myType, I will get
"CHEERFUL" but actually, what i really want to get is "always wears a smile
on his face".
can someone advise me how i can achieve this?? sounds simple but i really
don't know how!! =(
thanks in advance!!
hwee
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