Peter Beckman wrote:
> if (($row = mysql_fetch_row($result))[3] == 'foo') {
> $user = $row;
> }
>
> or
>
> $bar = explode('#', $str)[2];PHP does not currently support this type of syntax in any form. You must assign the return value of a function to a variable if you want to access it as an array. -Stut -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
