If all you want is a unique list of "adr_one_region" codes, then use the
DISTINCT keyword in your SQL:
SELECT DISTINCT adr_one_region FROM egw_addressbook WHERE cat_id='8' ORDER BY
adr_one_region
-TG
= = = Original message = = =
Hello everyone....
I'm back working on the website again... I'm having lots of fun.
I have a sql query that looks at one field in a database. (result2 query)
Then i have mysql_fetch_array statement.
I then use this array to print links on the page.
Works fine except I don't want duplicate links.
It creates links for the states. If we have four customers from Pennsylvania.
This current process gives me four different "PA" links on my page.
I need a statement that says...if its already printed...don't print it...
Thanks...
Here is my code:
<html>
<body>
<?php
$db = mysql_connect("HOST", "USERNAME", "PASSWORD");
mysql_select_db("DATABASE",$db);
if ($_GET[area]=="")
$master = mysql_query("SELECT * FROM egw_addressbook
WHERE cat_id='8' ORDER BY org_name", $db);
else
$master = mysql_query("SELECT * FROM egw_addressbook
WHERE cat_id='8' and adr_one_region='$_GET[area]' ORDER BY org_name", $db);
$result2 = mysql_query("SELECT adr_one_region FROM egw_addressbook
WHERE cat_id='8' ORDER BY adr_one_region", $db);
if ($area = mysql_fetch_array($result2))
echo "Sort by State: ";
do
echo "<a
href='index.php?area=$area[adr_one_region]'>$area[adr_one_region]</a>\n";
echo " - ";
while ($area = mysql_fetch_array($result2));
echo "<a href='index.php?area='>ALL</a>\n";
else
echo "ERROR";
if ($myrow = mysql_fetch_array($master))
echo "<CENTER>\n";
echo "<table border=0>\n";
echo "<img src=file.jpg width='611' height='136'>\n";
echo "<BR>\n";
echo "<BR>\n";
do
printf("<tr> <td></td><td><b>%s</b></td><td></td><td></td><td>%s</td></tr>\n",
$myrow["org_name"], $myrow["fn"]);
printf("<tr> <td></td><td>%s</td><td></td><td></td><td>%s</td></tr>\n",
$myrow["adr_one_street"], $myrow["tel_work"]);
printf("<tr> <td></td><td>%s, %s
%s</td><td></td><td></td><td></td><td></td></tr>\n",
$myrow["adr_one_locality"], $myrow["adr_one_region"],
$myrow["adr_one_postalcode"]);
while ($myrow = mysql_fetch_array($master));
echo "</table>\n";
echo "</CENTER>\n";
else
echo "Sorry, no records were found!";
?>
</body>
</html>
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