Please fix your reply-to address.
It
is an SQL query (probably MySQL, but perhaps SQLite or possibly even PGSQL or
mSQL):
The line after $query should tell you what uses it ;)
$query="SELECT TABLE $tablename;";
if (mysql_query($query, $link)) {
echo($indent."The table, '$tablename', was successfully opened.<br />\n");
}
To make things even stranger, it works fine in the original program that I put
it in (although what, if anything, it does is beyond me), but fails when I try
it in another program (yes, I took care of $tablename).
What's the exact query that's run? Maybe $tablename contains more than
just a table name.
Different mysql version? Maybe it was in an older version of mysql but
they removed it.
It doesn't work in mysql5 or mysql4.0, maybe it does in an older version
though.
Looks like you're trying to check that the mysql user you connected as
has access to that table.
--
Postgresql & php tutorials
http://www.designmagick.com/
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
