AHH. I figured it out. I needed to use GROUP BY SELECT `cartoons`.`reference`, `cartoons`.`cartoon_title`, `cartoons`.`date_added`, IFNULL(AVG(`ratings`.`rating`), 0) as 'average_rating' FROM `cartoons` INNER JOIN `ratings` ON `cartoons`.`reference` = `ratings`.`content_reference` GROUP BY `ratings`.`content_type`, `ratings`.`content_reference` ORDER BY `cartoons`.`cartoon_title` ASC ----- Original Message ----- From: Ron Piggott To: php-db@lists.php.net Sent: Sunday, September 06, 2009 9:28 PM Subject: Averages
I am making a voting / rating application. I am working on the following query: SELECT `cartoons`.`reference`, `cartoons`.`cartoon_title`, `cartoons`.`date_added`, IFNULL(AVG(`ratings`.`rating`), 0) as 'average_rating' FROM `cartoons` INNER JOIN `ratings` ON `cartoons`.`reference` = `ratings`.`content_reference` WHERE `ratings`.`content_type` =3 ORDER BY `cartoons`.`cartoon_title` ASC I only get 1 result because IFNULL(AVG(`ratings`.`rating`), 0) is giving me the result of all the ratings every submitted where `ratings`.`content_type` =3. The '3' is symbolic of cartoons. What I am wanting to do is show on the web page a list of all the cartoons and their current rating. In my ratings table I have a content_type column to know what area of the web site is being voted of (3 for cartoons) and I have content_reference which referrs to the auto_increment value of cartoons.reference. How do I be more specific with the AVG so I will get a rating for each cartoon in the table? Ron
