I tried the below code too considering may be the localhost is really dumb
and we need to tell each and every condition. But still its not working :(
$tweet = $search->plugin->ListViewValue();
$fb = $search->facebook->ListViewValue();
if($tweet=="" && $fb=="")
{
echo "";
}
elseif($fb=="" && $tweet!="")
{
echo '<a href="'.$search->plugin->ListViewValue().'"><img
src="images/twitter.gif" width="22" height="23"/></a></a>';
}
elseif($tweet=="" && $fb!="")
{
echo '<a
href="'.$search->facebook->ListViewValue().'"><img
src="images/facebook.gif" width="22" height="23"/></a></a>';
}
elseif($fb!="" && $tweet!="")
{
echo '<a href="'.$search->plugin->ListViewValue().'"><img
src="images/twitter.gif" width="22" height="23"/></a></a>'.'<a
href="'.$search->facebook->ListViewValue().'"><img
src="images/facebook.gif" width="22" height="23"/></a></a>';
}
On Tue, Mar 13, 2012 at 9:44 PM, Matijn Woudt <[email protected]> wrote:
> On Tue, Mar 13, 2012 at 4:53 PM, Gu®u <[email protected]> wrote:
> > No Michael, your code is also not working. What you have understood is
> > correct. let me explain it to others too.
> >
> > If variable twitter and facebook are empty don't echo anything,
> >
> > if variable twitter has a value and facebook is empty echo out only
> twitter,
> >
> > if variable twitter has no value and facebook has a value echo out
> facebook
> > only,
> >
> > and finally if both has values echo out both.
> >
> > Basically I want to echo out only if there is some value in the database.
> > But in my case both the images are echoing out.
> >
>
> That's exactly what my code does too, except it's a bit simpler. If
> mine isn't working too, then your input is probably different, try a
> var_dump on the ListViewValue() items.
>
> - Matijn
>
--
*Best,
*
*Gu®u*
