ID: 8860
Updated by: cynic
Reported By: [EMAIL PROTECTED]
Old-Status: Open
Status: Closed
Bug Type: Scripting Engine problem
Assigned To:
Comments:
no. it will echo contents of $three. if you don't have that variable in current scope,
it'll echo null, and, depending on your settings, emit a warning.
Previous Comments:
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[2001-01-23 09:57:18] [EMAIL PROTECTED]
according to Zeev this should work:
$test = Array("one","two","three","four"); $var = 'test[2]'; echo $$var; /* should
echo "three" */
But with it doesn't
Greetz,
Wico
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Full Bug description available at: http://bugs.php.net/?id=8860
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