From: [EMAIL PROTECTED] Operating system: Unix PHP version: 4.0.4pl1 PHP Bug Type: Feature/Change Request Bug description: Allow show_source output to be set as a variable Can you make it so that when you call show_source that you can set its output as a variable: ie: $var = show_source( $file ); Thanks! Brad Taylor Senior Web Content Developer BradCom Industries LTD -- Edit Bug report at: http://bugs.php.net/?id=9444&edit=1 -- PHP Development Mailing List <http://www.php.net/> To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
