ID: 9466
Updated by: cnewbill
Reported By: [EMAIL PROTECTED]
Old-Status: Open
Status: Closed
Bug Type: Unknown/Other Function
Assigned To:
Comments:
It does work with a CVS snapshot.
<?php
$eval = "return 123;";
$e = eval("$eval");
var_dump($e);
?>
OUTPUT
int(123)
You also did not have a ";" terminating your return 0 line. Fix your code and try
again. If the problem persists try a CVS snapshot from http://snaps.php.net and
reopen this report.
Previous Comments:
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[2001-02-26 13:32:53] [EMAIL PROTECTED]
When i create a piece of code with eval like :
eval = "if (!isset($$value)) {";
eval .= " return 0; "
eval .= "}";
eval("$eval");
The return statement doesn't work.
It works with earlier versions of php. (php3).
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