ID: 12161
Updated by: joey
Reported By: [EMAIL PROTECTED]
Old Status: Open
Status: Feedback
Bug Type: Unknown/Other Function
Operating System: Windows 98
PHP Version: 4.0.6
New Comment:
This is not a PHP bug, it is a bug in your code, related to
the use of preg_replace.
Example: printdate("ddd");
You're expecting:
Mon
You should be getting:
7on
Why?
Mon is becoming date("M")on, or something like it.
I don't know if this is what preg_replace SHOULD be
doing or not...it seems to be making multiple passes
until it can no longer replace anything. Could someone
who knows about preg_replace please verify whether this
is the correct behavior or not?
In the meantime, I fixed the userland code so that it performs
as you expected. You can find it at http://www.joeysmith.com/phpdate.phps
Previous Comments:
------------------------------------------------------------------------
[2001-07-14 04:24:44] [EMAIL PROTECTED]
PHP Authors,
My names are James Hitz, author of http://jamhitz.tripod.com a website that provides
free PHP tutorials.
I was creating a tutorial on user-defined functions and was working on one that
accepts a string containing a date format (eg. dd-mmm-yy) and outputs the date in the
specified format. The code is as follows:
<?php
function printdate($subject){
$search = array(
"/[d]{4}/i",
"/[d]{3}/i",
"/[d]{2}/i",
"/[d]{1}/i",
"/[m]{4}/i",
"/[m]{3}/i",
"/[m]{2}/i",
"/[m]{1}/i",
"/[y]{3,4}/i",
"/[y]{1,2}/i" );
$replace = array(
date("l"),
date("D"),
date("d"),
date("j"),
date("F"),
date("M"),
date("m"),
date("n"),
date("Y"),
date("y") );
$newdate = preg_replace($search,$replace, $subject);
//return the formatted date
return $newdate;
}
?>
On my Win 98 (Second Edition) system running php version 4.06, I evoked the following
above functrion using the following code snippet:
print printdate("dddd ddd, dd d m mm mmm mmmm y yy yyy yyyy");
This produced the following output:
Thurs12a01 Thu, 12 12 7 07 Jul Jul01 01 01 2001 2001
Aparrently, I expected this to have produced something like this:
Thursday Thu, 12 12 7 07 Jul July 01 01 2001 2001
The parsing of the date() function seems not to act 'normal'. The documentation I
have states as follows in regard to the date() function:
<QUOTE>
date
(PHP 3, PHP 4 )
date -- Format a local time/date
Description
string date (string format [, int timestamp])
Returns a string formatted according to the given
format string using the given timestamp or the current
local time if no timestamp is given.
The following characters are recognized in the format
string:
d - day of the month, 2 digits with leading zeros; i.e.
"01" to "31"
D - day of the week, textual, 3 letters; i.e. "Fri"
F - month, textual, long; i.e. "January"
j - day of the month without leading zeros; i.e. "1"
to "31"
l (lowercase 'L') - day of the week, textual, long;
i.e. "Friday"
m - month; i.e. "01" to "12"
M - month, textual, 3 letters; i.e. "Jan"
n - month without leading zeros; i.e. "1" to "12"
r - RFC 822 formatted date; i.e. "Thu, 21 Dec 2000 16:01:07 +0200"
Y - year, 4 digits; i.e. "1999"
y - year, 2 digits; i.e. "99"
z - day of the year; i.e. "0" to "365"
</QUOTE>
Is this a bug in the code or a bug in the documentation? Seems to me like one of
those. Please advise. I am making a tutorial that will make use of the above function
and would appreciate if you would tell me what to tell my audience.
The tutorials I am make are very good for all - even complete beginners, so you can
bundle them in your PHP distributions, or you can point users to
http://jamhitz.tripod.com. All tutorials are free.
Thanking you.
James N. Hitz
[EMAIL PROTECTED]
------------------------------------------------------------------------
Edit this bug report at http://bugs.php.net/?id=12161&edit=1
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