ID: 14343
Updated by: derick
Reported By: [EMAIL PROTECTED]
Old Status: Open
Status: Bogus
Bug Type: Arrays related
Operating System: Linux/PPC
PHP Version: 4.0.5
New Comment:
Not a bug... PHP indeed tries to convert 'foobar' to a number, and because that is not
really possible, it becomes 0. That's why there is that third parameter too.
Derick
Previous Comments:
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[2001-12-04 15:37:18] [EMAIL PROTECTED]
On my system, in_array wrongly returns true when searching
for zero in arrays that don't contain zero:
Sample code:
in_array(0, array('foobar'));
-->TRUE
If I add the third parameter, it returns the correct
result:
print in_array(0, array('foobar'), true);
-->FALSE
However, I'm pretty sure that 0 doesn't coerce to 'foobar'
- I don't think PHP is that loosely-typed :)
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Edit this bug report at http://bugs.php.net/?id=14343&edit=1
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