My code is much more extense than this, but I guess this is the source of my
problem.
"arquivo" is a member of a form, it is a file type, declared like <input
type="file" name="arquivo">...
I need to know if there is a file selected or not, that is the reason of the
bug.
When I run this code, through the form it does not print anything, even when
I choose a file on the previous html (html with a form, with an action
calling this script...) My version of PHP is 4.x
<?php
$nome = $_POST['nome'];
$des = $_POST['des'];
$eng = $_POST['eng'];
$id = $_POST['id'];
$tabela = $_POST['tabela'];
$tabela_nova = $_POST['dd_tipo'];
$arquivo = $_FILES['arquivo']['name'];
//Conexao com BD...
printf("%s",$arquivo);
?>
Why it is happenig???
_________________________________________
Daniel Castro ICQ#: 12919017
[EMAIL PROTECTED]
[EMAIL PROTECTED]
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