php-general Digest 20 Apr 2009 03:15:48 -0000 Issue 6076
Topics (messages 291666 through 291670):
self in inherited methods
291666 by: Alex S Kurilo aka Kamazee
How do I access a local variable?
291667 by: abdulazeez alugo
291668 by: Chris
291669 by: Paul M Foster
DATE / strtotime
291670 by: Ron Piggott
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--- Begin Message ---
Is it right that 'self' in inherited method still points to the parent?
If it is, can you explain it? It makes me worry :)
A piece of code below for example
<?php
class MyParent {
const NAME = 'MyParent';
public function get_instance() {
return new self;
}
public function get_another_instance() {
$class_name = get_class($this);
return new $class_name;
}
public function get_name() {
return self::NAME;
}
}
class MyClass extends MyParent {
const NAME = 'MyClass';
}
$a = new MyClass;
$b = $a->get_instance();
$c = $a->get_another_instance();
echo $a->get_name(),"\n";
echo get_class($b),"\n";
echo get_class($c),"\n";
?>
--- End Message ---
--- Begin Message ---
Hi guys,
I have a function inside which I set alocal variable to store a result. Can I
access this variable in another function? if yes then how?
function tbl1($entrytitle, $entrytext)
{
global $conn;
$result= mysql_query("INSERT INTO tbl1(tbl1_id, title, text)
VALUES('NULL', '$entrytitle', '$entrytext')", $conn);
$tbl_id=mysql_insert_id($conn);// this is the local variable I'm setting
to get the last auto increment id
}
Now I wish to access that variable in another function thus:
function tbl2($name, $entrytitle, $entrytext)
{
global $conn;
$result =mysql_query("INSERT INTO tbl2(tbl1_id, name, title, text)
VALUES('$tbl1_id', '$name', '$entrytitle',
'$entrytext' )", $Conn);
}
Or is there a better way to store the variable?
Thanks in advance.
Alugo Abdulazeez
www.frangeovic.com
_________________________________________________________________
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--- End Message ---
--- Begin Message ---
abdulazeez alugo wrote:
Hi guys,
I have a function inside which I set alocal variable to store a result. Can I
access this variable in another function? if yes then how?
No, you can't. You either need to pass it back (recommended) or make it
global (not recommended).
function tbl1($entrytitle, $entrytext)
{
global $conn;
$result= mysql_query("INSERT INTO tbl1(tbl1_id, title, text)
VALUES('NULL', '$entrytitle', '$entrytext')", $conn);
$tbl_id=mysql_insert_id($conn);// this is the local variable I'm setting
to get the last auto increment id
return $tbl_id;
}
Now I wish to access that variable in another function thus:
function tbl2($name, $entrytitle, $entrytext)
{
$other_id = tbl1($entrytitle, $entrytext);
echo $other_id;
global $conn;
$result =mysql_query("INSERT INTO tbl2(tbl1_id, name, title, text)
VALUES('$tbl1_id', '$name', '$entrytitle', '$entrytext' )", $Conn);
}
PS : look up mysql_real_escape_string for when you save your data.
--
Postgresql & php tutorials
http://www.designmagick.com/
--- End Message ---
--- Begin Message ---
On Mon, Apr 20, 2009 at 12:54:27AM +0100, abdulazeez alugo wrote:
>
> Hi guys,
>
> I have a function inside which I set alocal variable to store a result. Can I
> access this variable in another function? if yes then how?
>
> function tbl1($entrytitle, $entrytext)
>
> {
>
> global $conn;
>
> $result= mysql_query("INSERT INTO tbl1(tbl1_id, title, text)
>
> VALUES('NULL', '$entrytitle', '$entrytext')", $conn);
>
> $tbl_id=mysql_insert_id($conn);// this is the local variable I'm setting
> to get the last auto increment id
>
> }
>
>
>
> Now I wish to access that variable in another function thus:
>
> function tbl2($name, $entrytitle, $entrytext)
>
> {
>
> global $conn;
>
> $result =mysql_query("INSERT INTO tbl2(tbl1_id, name, title, text)
>
> VALUES('$tbl1_id', '$name', '$entrytitle',
> '$entrytext' )", $Conn);
>
> }
>
>
>
> Or is there a better way to store the variable?
If a variable is local to a function, there is no way to access that
variable outside that function. You can pass it back as a return value
from the original function, or make it global (not advised) to make it
visible in other functions.
Paul
--
Paul M. Foster
--- End Message ---
--- Begin Message ---
Where $date_reference is 2009-04-18 the following code gives me a day of
1969-12-30. How do I get it to be 2009-04-17?
$previous_date = strtotime("-1 days", $date_reference);
$previous_date = date('Y-m-d', $previous_date);
echo $previous_date; outputs 1969-12-30
Ron
--- End Message ---
