php-general Digest 26 Sep 2010 10:03:42 -0000 Issue 6960
Topics (messages 308311 through 308315):
Re: if/elseif being treated as if/if
308311 by: tedd
308312 by: tedd
Array question
308313 by: MikeB
308314 by: chris h
308315 by: [email protected]
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--- Begin Message ---
At 3:54 PM -0400 9/24/10, Bob McConnell wrote:
From: tedd
At 2:23 PM -0400 9/24/10, Bob McConnell wrote:
>>A switch works when a single test can dispatch all possible branches.
If
you have a series of tests where each looks for a different subset of
>>conditions, you need an elseif.
Not so, O'wise one.
This will work:
switch(1)
{
case $a > $b:
/* whatever
break;
case $c == 1:
/* whatever
break;
case $d == 'this works':
/* whatever
break;
}
Granted, it's not the normal way a switch works in some other
languages, but it does work in PHP. :-)
That is just so wrong, it can't actually be taken seriously. There is
simply no justification for such broken logic.
Bob McConnell
I take it seriously. In fact, I think it's a very good method of
making several different comparisons in one control structure. For
me, it is easy to understand, document, and maintain. Obviously, your
mileage varies.
But besides the point, all I was showing was that your claim --
A switch works when a single test can dispatch all possible
branches. If you have a series of tests where each looks for a
different subset of conditions, you need an elseif.
-- was false. I don't need an elseif and never have. There has always
been a way around using an elseif. The powers that be could boot that
control and I would never miss it.
Cheers,
tedd
--
-------
http://sperling.com/
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--- Begin Message ---
At 9:04 PM +0100 9/24/10, Ashley Sheridan wrote:
I don't often use this type of logic, but I have used it before and
it's served me well. Essentially, a switch is a glorified if
statement, and I find them a lot nicer to read and write than a
series of if/elseif blocks.
Thanks,
Ash
Ash:
Exactly my take.
I wouldn't live next door to an ELSEIF even if it lived in a good
neighborhood. :-)
However, I always thought (maybe in error) that the switch control
(CASE statement) was derived from the computed GOTO rather than from
the three-way IF statement.
One can make the argument that the ELSE IF statement first surfaced
circa 1977 in FORTRAN 77 and the CASE statement came later in FORTRAN
90 circa 1991. But I know I was using computed GOTOs and GOSUBs long
before then.
In any event, to me the computed GOTO is more like the CASE statement
than ELSE IF.
Cheers,
tedd
--
-------
http://sperling.com/
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--- Begin Message ---
I have the following code:
$query = "SELECT * FROM classics";
$result = mysql_query($query);
if (!$result) die ("Database access failed: " . mysql_error());
$rows = mysql_num_rows($result);
for ($j = 0 ; $j < $rows ; ++$j)
{
$results[] = mysql_fetch_array($result);
}
mysql_close($db_server);
My question, in the loop, why does tha author use:
$results[] = mysql_fetch_array($result);
instead of (as I would expect):
$results[$j] = mysql_fetch_array($result);?
What PHP magic is at work here?
Thanks.
--- End Message ---
--- Begin Message ---
Mike,
$results[] will automatically push a value unto the end of an array.
So doing this...
------
$magic = array();
$magic[] = 'a';
$magic[] = 'b';
$magic[] = 'c';
-----
is exactly this same as doing this...
------
$normal = array();
$normal[0] = 'a';
$normal[1] = 'b';
$normal[2] = 'c';
-----
And yes, in your example "$results[]" would be equivalent to "$results[$j]"
For more reference:
http://www.php.net/manual/en/language.types.array.php
Chris H.
On Sat, Sep 25, 2010 at 4:31 PM, MikeB <[email protected]> wrote:
> I have the following code:
>
> $query = "SELECT * FROM classics";
> $result = mysql_query($query);
>
> if (!$result) die ("Database access failed: " . mysql_error());
> $rows = mysql_num_rows($result);
>
> for ($j = 0 ; $j < $rows ; ++$j)
> {
> $results[] = mysql_fetch_array($result);
> }
>
> mysql_close($db_server);
>
> My question, in the loop, why does tha author use:
>
> $results[] = mysql_fetch_array($result);
>
> instead of (as I would expect):
>
> $results[$j] = mysql_fetch_array($result);?
>
> What PHP magic is at work here?
>
> Thanks.
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
--- End Message ---
--- Begin Message ---
I'd also like to add to that:
$array = array();
$array[] = 'text';
$array[2] = 123;
$array[] = 'hello';
Would output:
$array(
0 => 'text',
2 => 123,
3 => 'hello',
);
Note the missing index 1, as php makes a numerical index that is one greater
than the highest already in use. As the index 2 was explicitly created, php
made the next one at 3.
Thanks,
Ash
http://www.ashleysheridan.co.uk
----- Reply message -----
From: "chris h" <[email protected]>
Date: Sat, Sep 25, 2010 22:05
Subject: [PHP] Array question
To: "MikeB" <[email protected]>
Cc: <[email protected]>
Mike,
$results[] will automatically push a value unto the end of an array.
So doing this...
------
$magic = array();
$magic[] = 'a';
$magic[] = 'b';
$magic[] = 'c';
-----
is exactly this same as doing this...
------
$normal = array();
$normal[0] = 'a';
$normal[1] = 'b';
$normal[2] = 'c';
-----
And yes, in your example "$results[]" would be equivalent to "$results[$j]"
For more reference:
http://www.php.net/manual/en/language.types.array.php
Chris H.
On Sat, Sep 25, 2010 at 4:31 PM, MikeB <[email protected]> wrote:
> I have the following code:
>
> $query = "SELECT * FROM classics";
> $result = mysql_query($query);
>
> if (!$result) die ("Database access failed: " . mysql_error());
> $rows = mysql_num_rows($result);
>
> for ($j = 0 ; $j < $rows ; ++$j)
> {
> $results[] = mysql_fetch_array($result);
> }
>
> mysql_close($db_server);
>
> My question, in the loop, why does tha author use:
>
> $results[] = mysql_fetch_array($result);
>
> instead of (as I would expect):
>
> $results[$j] = mysql_fetch_array($result);?
>
> What PHP magic is at work here?
>
> Thanks.
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
--- End Message ---
