php-general Digest 28 Sep 2012 13:27:30 -0000 Issue 7984
Topics (messages 319289 through 319294):
Round help needed
319289 by: Chris Payne
319290 by: Daniel Brown
Re: Static constructor support
319291 by: shiplu
Here's my rounding
319292 by: Chris Payne
319293 by: Simon J Welsh
319294 by: Jim Giner
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--- Begin Message ---
Hi everyone,
I'm having one of those nights where nothing is working, please help
What I have is this:
$rounded_number = round($test, -3);
Here's the problem i'm having, I need it to increment to the nearest 1000
but it seems to only work if the number is over 500. For example:
123666 WILL round to 124000 BUT if I put 123085 (As an example) it doesn't
round it, it just stays at 123085 - I know it's probably something totally
ridiculously simple but i'm having a mental block tonight.
Any help would really be appreciated.
Chris
http://www.youtube.com/user/zoolook3264
--- End Message ---
--- Begin Message ---
On Thu, Sep 27, 2012 at 11:05 PM, Chris Payne <oxygene...@gmail.com> wrote:
> Hi everyone,
>
> I'm having one of those nights where nothing is working, please help
>
> What I have is this:
>
> $rounded_number = round($test, -3);
>
> Here's the problem i'm having, I need it to increment to the nearest 1000
> but it seems to only work if the number is over 500. For example:
>
>
> 123666 WILL round to 124000 BUT if I put 123085 (As an example) it doesn't
> round it, it just stays at 123085 - I know it's probably something totally
> ridiculously simple but i'm having a mental block tonight.
>
> Any help would really be appreciated.
Sounds like one of those "should be obvious, but isn't" issues.
This gives the desired result:
<?php echo round(123085,-3); ?>
So I wonder if it's your variable (perhaps even type-casting) or
some other portion of your code. Can you elaborate and share some of
your bytes with the class, Mr. Payne?
--
</Daniel P. Brown>
Network Infrastructure Manager
http://www.php.net/
--- End Message ---
--- Begin Message ---
Somewhere in Internet I found this form.
class MyClass{
static private $somevar;
static public function init(){
}
} MyClass::init();
Now I am using this consistently.
--
Shiplu.Mokadd.im
ImgSign.com | A dynamic signature machine
Innovation distinguishes between follower and leader
--- End Message ---
--- Begin Message ---
$test2 = '253177';
echo $tes2 . " rounded to: ";
$rounded_number = round($test2,-3);
echo $rounded_number;
Is it SUPPOSED to happy a number is sent to this little system and it's
SUPPOSED to round the number up. So if the number was 144035 the system
should look at it and say "Hey uo,
we need to round this up" So basicially I need it to convert in
thousands. Even if the total is a fraction over it still needs to ne
calculated as the next thousand up.
Sprru of o'm confusing you, i'm very tired. So basically, just make the
last 4 numbers always round up. 255000 would be correct - 255590 would
beINSORERECT as it should display 255600.
Hope that helped someone to help me :-)
xxx
Chris
--- End Message ---
--- Begin Message ---
On 28/09/2012, at 6:08 PM, Chris Payne <oxygene...@gmail.com> wrote:
> $test2 = '253177';
> echo $tes2 . " rounded to: ";
> $rounded_number = round($test2,-3);
> echo $rounded_number;
>
> Is it SUPPOSED to happy a number is sent to this little system and it's
> SUPPOSED to round the number up. So if the number was 144035 the system
> should look at it and say "Hey uo,
> we need to round this up" So basicially I need it to convert in
> thousands. Even if the total is a fraction over it still needs to ne
> calculated as the next thousand up.
>
> Sprru of o'm confusing you, i'm very tired. So basically, just make the
> last 4 numbers always round up. 255000 would be correct - 255590 would
> beINSORERECT as it should display 255600.
>
> Hope that helped someone to help me :-)
>
> xxx
> Chris
I would use something similar to $rounded_number = ceil($test2/1000)*1000;
---
Simon Welsh
Admin of http://simon.geek.nz/
--- End Message ---
--- Begin Message ---
On 9/28/2012 2:11 AM, Simon J Welsh wrote:
On 28/09/2012, at 6:08 PM, Chris Payne <oxygene...@gmail.com> wrote:
$test2 = '253177';
echo $tes2 . " rounded to: ";
$rounded_number = round($test2,-3);
echo $rounded_number;
Is it SUPPOSED to happy a number is sent to this little system and it's
SUPPOSED to round the number up. So if the number was 144035 the system
should look at it and say "Hey uo,
we need to round this up" So basicially I need it to convert in
thousands. Even if the total is a fraction over it still needs to ne
calculated as the next thousand up.
Sprru of o'm confusing you, i'm very tired. So basically, just make the
last 4 numbers always round up. 255000 would be correct - 255590 would
beINSORERECT as it should display 255600.
Hope that helped someone to help me :-)
xxx
Chris
I would use something similar to $rounded_number = ceil($test2/1000)*1000;
---
Simon Welsh
Admin of http://simon.geek.nz/
From my days as a math major, rounding doesn't always go up - it goes
to the nearest level that you have indicated. As Simon shows you, you
want to ceil to always go up, and floor to always go down. Neat
function names actually... :)
--- End Message ---
