try this:
$sql = "SELECT * FROM table
WHERE town LIKE '%$search_data%' ";
if ($reference != "")
$sql .= "OR whatever";
""James, Yz"" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
93vs2p$cng$[EMAIL PROTECTED]">news:93vs2p$cng$[EMAIL PROTECTED]...
> OK, I got a simple search page working (thanks to all of you who helped
me).
>
> Another simple question for you. If I had a search and the data to be
> searched needs to be determined by check boxes, How would I write the
sql>?
> Like this?
>
> $sql = "SELECT * FROM table
> WHERE town LIKE '%$search_data%' OR street LIKE '%$search_data%' ";
>
> Is "OR" even the correct syntax? Here's how I tried it, which didn't give
> any results.....
>
> (Where reference is the id number (or map reference) and search_data is
the
> text field for users to tpye the query.
>
> if ($reference != "")
> $search_reference = "OR id LIKE '%$reference%'";
> }
>
> $sql = "SELECT * FROM table
> WHERE town LIKE '%$search_data%' $search_reference";
>
> $result = @mysql_query($sql,$connection)
> or die (mysql_error());
>
> $num = mysql_num_rows($result);
>
>
> TIA,
> James.
>
>
>
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