> This only applies to PHP 4.0.4 > > Back with PHP 4.0.2, I could do this: > > <?PHP > $string = "[["; > $string = preg_replace("/(\W)/", "\\\\1", $string); > ?> > > $string would then contain "\[\[". > > Now, if I use that same code, $string contains "\\1\\1\\1\\1". > > I tried to compensate for this using PHP's new ability to allow > perl syntax in the replace section. > > <?PHP > $string = "[["; > $string = preg_replace("/(\W)/", "\\$1", $string); > ?> > > That leaves $string with "\$1\$1\$1\$1". Which tells me it thought > I was backreferencing the $. So, to combat said assumption, I tried > three, four, even five slashes in front of $1, and nothing worked. > All I got were variations of "\$1\$1\$1\$1". > > I have to assume this is a bug, since this worked back in 4.0.2 which > I stopped using due to segfaults under certain circumstances. > > Ideas? It is indeed a bug - I fixed it in CVS version if you want to try that. -Andrei * A feature is a bug with seniority. * -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]