> This only applies to PHP 4.0.4
>
> Back with PHP 4.0.2, I could do this:
>
> <?PHP
> $string = "[[";
> $string = preg_replace("/(\W)/", "\\\\1", $string);
> ?>
>
> $string would then contain "\[\[".
>
> Now, if I use that same code, $string contains "\\1\\1\\1\\1".
>
> I tried to compensate for this using PHP's new ability to allow
> perl syntax in the replace section.
>
> <?PHP
> $string = "[[";
> $string = preg_replace("/(\W)/", "\\$1", $string);
> ?>
>
> That leaves $string with "\$1\$1\$1\$1". Which tells me it thought
> I was backreferencing the $. So, to combat said assumption, I tried
> three, four, even five slashes in front of $1, and nothing worked.
> All I got were variations of "\$1\$1\$1\$1".
>
> I have to assume this is a bug, since this worked back in 4.0.2 which
> I stopped using due to segfaults under certain circumstances.
>
> Ideas?
It is indeed a bug - I fixed it in CVS version if you want to try that.
-Andrei
* A feature is a bug with seniority. *
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