> When you are using mysql_insert_id, you don't want to pass it
> the result of your previous SQL statement as in:
> $result = mysql"mydb", "My SQL statement", $my_connect) ;
> $last_id = mysql_insert_id($result)
This is what it sounds like it's looking for in the documentation. It
could be just how I'm reading it. :p
> Rather, you want to pass it the link identifier from your
> mysql_connect like:
> $result = mysql("mydb", "My SQL statement", $my_connect) ;
> $last_id = mysql_insert_id($my_connect)
Tried this, too, with no luck. :( I'm using mysql_pconnect() and
mysql_connect() and neither seems to help my situation.
Chris
