At 9:08 PM -0800 1/24/01, jeremy brand wrote:
>$array[0] will be the lang_pref and $array[1] will be the
>currency_pref.
>
>Jeremy
An easy way to read the returned array values into scalar variables is:
list($lang_pref, $currency_pref) = PrefChange($language,
$currency, $state);
You can only do this if your PrefChange function _always_ returns the
same number of elements (two here; it could be any number). If you
have a function that - for example - returns a 2-element array or
FALSE if there's an error, then you have to do something a little
more complex:
$Stuff = PrefChange($language, $currency, $state);
if (is_array($Stuff))
{
# ...do stuff with $Stuff !
} else {
# ...show error message
}
- steve
>Jeremy Brand :: Sr. Software Engineer :: 408-245-9058 :: [EMAIL PROTECTED]
>http://www.JeremyBrand.com/Jeremy/Brand/Jeremy_Brand.html for more
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>On Thu, 25 Jan 2001, Jamie wrote:
>
>> Date: Thu, 25 Jan 2001 13:04:27 +0800
>> From: Jamie <[EMAIL PROTECTED]>
>> To: PHP <[EMAIL PROTECTED]>
>> Subject: [PHP] multiple function returns
>>
>> Can anyone help me I'm trying to read two results from a function by passing
>> them out via an array but I'm not sure how to access them once I have done
>> that. In the PHP manual it shows a list call which I can't seem to even find
>> what the hell it does the code below runs without any errors but does not
>> seem to work.
>>
>> here the function gest passed the language and currency preference and a
>> variable (1,0) to decide what it will do with them - update the preferences
>> of the user or read out and define the preferences. (once updated I want it
>> to read out the prefs aswell)
>>
>> function PrefChange($lang,$curry,$state){
>> global $DB_Server, $HTTP_Host, $DB_Login, $DB_Password, $DB_Name, $DocRoot ;
>>
>> if ($state){//read preferences from page
>> if (!($result = mysql_db_query($DB_Name,"SELECT language_pref,
>> currency_pref FROM users WHERE user_id ='$cookie_user'"))){
>> DisplayErrMessage(sprintf("internal error %s %s %s %d:%s\n",$DB_Server,
>> $DB_Login, $DB_Password,
>> mysql_errno(), mysql_error()));
>> while ($row = mysql_fetch_array($results)){
>> $lang_pref = $row["language_pref"];
>> $currancy_pref = $row["currency_pref"];
>> return array($lang_pref,$currancy_pref);
>> }
>> }
>> } else {///update preferences from page
>> if (!($result = mysql_db_query($DB_Name,"UPDATE users SET
>> language_pref='$lang' AND currency_pref='$curry' WHERE
>> user_id='$cookie_user'"))){
>> DisplayErrMessage(sprintf("internal error %s %s %s %d:%s\n",$DB_Server,
>> $DB_Login, $DB_Password,
>> mysql_errno(), mysql_error()));
>> PrefChange(0,0,1) ;
>> }
>> }
>> }
>>
>>
>> an example of what I'd like to do when calling the function (here I'm only
>> reading the prefrences from the DB ), a select box that is showing the
>> preference that is chosen with the preference read from the above function
>> and the list created by the function below
>>
>> <select name="form_lang_pref" style="font-family:verdana,
>> Arial;font-size:8pt" CLASS:menu">
>> <?
>> list ($form_language_pref, $form_currency_pref) = PrefChange(0,0,1);
>>
>> $select_id = $form_language_pref;
>> $db = mysql_connect("$DB_Server", "$DB_Login, $DB_Password");
>> mysql_select_db("$DB_Name",$db);
>> $results = mysql_query("SELECT * FROM language ORDER BY language
>> ",$db);
>>
>> while ($row = mysql_fetch_array($results)){
>> $rowid = $row["language_id"];
>> $name = $row["language"];
>> if ($rowid == $select_id) {
> > echo("<option SELECTED value=\"$id\">$name</option>\n");
>> } else {
>> echo("<option value=\"$id\">$name</option>\n");
>> }
>> // endwhile;
>> }
>> echo("</select>");
>> ?>
> >
>
--
+--- "They've got a cherry pie there, that'll kill ya" ------------------+
| Steve Edberg University of California, Davis |
| [EMAIL PROTECTED] Computer Consultant |
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