> > Anybody knows if this sourcecode is correct to calculate the 
> > numbers of days in certain date ?
> Why are you going through all that effort?
> $janOne  = mktime( 0, 0, 0, 1, 1, date( "Y" ));
> $myDate = mktime( 0, 0, 0, $m, $d, $y );
> $daysInYear = ( $myDate - $janOne ) / 86400;
> That should do it for you...

Or, just found this (I thought there this was available, but missed
it the first time)

echo date( "z" );

Chris

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