On Monday 12 February 2001 01:31, Scott Mebberson wrote:
> I understand that as of version 3.24, MySQL will support subselects.
> But untill then (because 3.23 is the latest stable release) I need to
> convert this SQL satement into something that can be used with v3.2? -
> the version just before the latest release.
>
> $search = "SELECT count(search_table.word) as score,
> search_table.qid,page_data.contents
> FROM search_table,page_data
> WHERE page_data.pID = search_table.qid AND search_table.word
> IN($querywords)
> GROUP BY search_table.qid
> ORDER BY score DESC";
Uh, perhaps I'm blind and/or dumb, but I just can't find a subselect in
that query.
The query as written here should run fine in any MySQL version
--
Christian Reiniger
LGDC Webmaster (http://sunsite.dk/lgdc/)
Nothing is more dangerous than an idea if it's the only one you have.
- Emil-Auguste Chartier, "Propos sur la religion", 1938
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