> hi, can anyone help me spot the parse error?
> It's throwing up on the first "if" line, and for the life of me I cannot
> find it! :)
>
> tia,
> andrew
>
> <?php
>
> include("db_connect_params.inc");
> $sql="select path from PHOTO where pid =1";
> $link_id = mysql_connect($host, $usr, $pass);
> $result = mysql_db_query($database, $sql, $link_id) or die("no result");
>
> if ((mysql_num_rows($result)) = 1)
Well I don't know if it will give a parse error or not, but you have made
the oh way too common C error in your IF statement.
> if ((mysql_num_rows($result)) = 1)
should be:
if ((mysql_num_rows($result)) == 1)
- John Vanderbeck
- Admin, GameDesign
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