>I' m searching a way to programmatically alternate 2 schedules each sunday
at 00:00. >Schedule1 start on first sunday and seven days later, schedule2
replace schedule1,and seven >days later, schedule1 replace schedule2 etc...
The *easiest* thing to do would be to run a cron job every Sunday at
midnight to flip something...
But, assuming you want to avoid that:
<?php
$now = time()
$weeknumber = $now % 52;
#So now I know which week of the year it is...
#How do I know if it's "before" or "after" Sunday?
#Easy:
$dayofweek = date("w", $now);
#So, now $dayofweek is either 0, for Sunday, or 1 for Monday, or...
#Problem, how to mix and match $weeknumber and $dayofweek to "change" on
Sundays
#Well, did this year start on a Wednesday, or what?
$newyeardayofweek = date("w", mktime(0, 0, 0, 1, 1, date("Y", $now)));
#This formula makes a lot more sense if you look at sample data:
/*
Format is:
The Day of week (Sun-Sat)
The day of the year 1-365
$weeknumber/$dayofweek
The right-hand column is 1/2
based on which schedule we want.
|
|
v
Thu Fri Sat
1 2 3 1
0/4 0/5 0/6
Sun Mon Tue Wed Thu Fri Sat
4 5 6 7 8 9 10 2
0/0 0/1 0/2 0/3 1/4 1/5 1/6
Sun Mon Tue Wed Thu Fri Sat
11 12 13 14 15 16 17 1
1/0 1/1 1/2 1/3 2/4 2/5 2/6
Sun Mon Tue Wed Thu Fri Sat
18 19 20 21 22 23 24 2
2/0 2/1 2/2 2/3 3/4 3/5 3/6
*/
#So, the "trick" is to switch on whether our day of the week is before
or after
#the day that started the year off.
if ((($weeknumber % 2) && ($dayofweek >= $newyeardayofweek)) ||
(!($weeknumber % 2) && ($dayofweek < $newyeardayofweek))){
include 'schedule1';
}
else{
include 'schedule2';
}
?>
Somebody else probably has a one-line answer. Oh well. :-)
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