At 17:40 11.03.2003, Doug Coning said:
--------------------[snip]--------------------
>header('Content-Type: image/jpeg');
>$im = imagecreatefromjpeg("001_SM77GR.jpg");
>imagejpeg($im,'',85);
>imagedestroy($im);
>
>I copied this code from PHP.net. However, when I run the above code, it
>doesn't download the image, it just shows the image in the browser. I'm
>using IE 6 for my browser.
>
>How I get PHP to download this image?
--------------------[snip]--------------------
To have a browser handling data it receives as downloadable file you must
set a Content-Type it cannot handle inline, and specify a disposition and
filename, such as:
Content-Type: application/octet-stream
Content-Disposition: attachment;filename="myfile.jpg"
Content-Length: 1234
Note that it is always a good idea to tell the browser the size of a file
it is about to receive. Since imagejpeg() outputs the stream directly and
doesn't giv you any size information, you may use output buffering to
obtain the stream, like:
ob_start();
imagejpeg($im, '', 85);
$image_size = ob_get_length();
$imgstream = ob_get_contents();
ob_end_clean();
// continue as outlined above
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment;filename="myfile.jpg"');
header('Content-Length: ' . $image_size);
echo $imgstream;
exit;
--
>O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
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