Thanks! That worked almost. It removed everything except for the 2 % signs.
How might I remove those as well? "Leif K-Brooks" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Try this (entirely untested!): > $final_footer = > preg_replace('%INCLUDE_FILE\\[[^\\]]*\\]%','',$final_footer); > > Nate wrote: > > >hi, > > > >i need to search $final_footer for a string such as > >%INCLUDE_FILE[/path/to/file]% (where /path/to/file could be anything) and > >delete it from the string. it being %INCLUDE_FILE[/path/to/file]% (not just > >/path/to/file) > > > >im new to regexps but im guessing I should use preg_match for this? > > > >Can someone give me a code example? > > > >thanks much > >Nate > > > > > > > > > > > > -- > The above message is encrypted with double rot13 encoding. Any unauthorized attempt to decrypt it will be prosecuted to the full extent of the law. > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
