/\b/
word boundary
instead of all the or's
Joshua Moore-Oliva wrote:
I'm kind of confused right now... when I call preg_replace_callback with a regular expression with brackets, sometimes I get an array back with multiple elements like
array(3) { [0]=> string(19) "http://www.aol.com " [1]=> string(0) "" [2]=> string(19) "http://www.aol.com " }
and I have no idea why... Why does the middle one have nothing in it? the regular expression was
$dumb_body = preg_replace_callback ( '/'
//Case spaceURLspace
. '([\s]http:\/\/[^\s]+[\s])'
. '|'
//Case URLspace
. '(^http:\/\/[^\s]+[\s])'
. '|'
//Case spaceURL
. '([\s]http:\/\/[^\s]+$)'
. '|'
//Case URL
. '(^http:\/\/[^\s]+$)'
. '/i'
, array( &$this, "storeUrlCallback" ), $dumb_body );
I am very confused at the point of the array in this function period... can anyone help?
Josh.
-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
