$EnteredDate = $date . "/" . $month . "/" . $year;

This would output DD/MM/YYYY if $date = DD, $month = MM and $year =
YYYY.

-----Original Message-----
From: Vicky [mailto:[EMAIL PROTECTED] 
Sent: 31 May 2003 15:06
To: PHP List
Subject: [PHP] 3 entries going into 1 field

Hi,

I have a registration form, but I would like to add a Date of Birth
section. Now, because of the different formats of writing it I want to
have 3 seperate drop down boxes, Date, Month and Year.

However, I then want those 3 dropdowns to go into one field in a mySQL
database, in DD/MM/YYYY format.

How can I acheive this, in simple language as I'm a newbie to this stuff
^_~

Thanks!
Vicky



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