Umm, you mean like: select i.id,d.description from items i, descriptions d where d.itemid = i.id;
? On Wed, 2003-07-23 at 12:32, Tony Crockford wrote: > Hi > > > Thanks for the help on previous questions, I now have an in principle > type question. > > I have a MySQL database - "items" in one table and "descriptions" in > another with a common key: item_ref > It is used to create a sort of categorised directory of the items. > (http://www.torbytes.co.uk) > > > each table has a status field the "items" have a default description and > the "descriptions" have a level classification. > > up to now been working through all the items and printing out the > descriptions at each level printing the default if I don't have a > matching description, but I now need to do the following: > > for a particular level print only the items (and their matching > description) where there is a matching description. (I hope you see what > I mean) > > since the items are categorised and I don't want any dead ends in my > tree structure I have to know if there's a description before I start > working through the items. > > I thought that this might be the way to do it: > > select all the item-ref values from the description table. > > step through this select array selecting the required fields from the > item table where item_ref=item_ref and adding them to another array. > > then step through that array building up the tree structure > > The trouble with it as I see it is: > > it's a lot of select calls to the database (one for every description > found) and I'm not sure how to add the fields found in the item table to > a new array. > > > Am I going at this the wrong way? > > Any help, clues or abuse accepted. > > Thanks > > Tony > > > > -- > NEO organizes my Outlook - check it out: > http://www.caelo.com/a/rl.php3?i=3NTVV -- Adam Voigt ([EMAIL PROTECTED]) Linux/Unix Network Administrator The Cryptocomm Group -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
