function test($arg1, $arg2, $arg3 = "") { if(isset($arg3)) { // do whatever with $arg3 } }
-----Original Message----- From: Jonathan Villa [mailto:[EMAIL PROTECTED] Sent: Thursday, August 21, 2003 7:56 PM To: [EMAIL PROTECTED] Subject: [PHP] How to make an argument optional...confirmation... I want to create a function with an optional argument/parameter but have never read a concrete answer on how to do it. This is what I am assuming function test(arg1,arg2,arg3 = null) { arg3 will be optional } is this correct? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php