[snip] $var=¨How are you¨; THE PROBLEM IS THAT I ALSO WANT TO USE $VAR IN SCRIPTTWO. [/snip]
Pleace $var in a hidden form element.
I tried... something like this
<input type="hidden" name="var2" value=¨<?php print $var2; ?>¨>
but it doesn't work. Maybe you mean something totaly different, can you show me what you mean.
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