you can use simply
exec("ls -l 2>&1;", $output) : if on linux OR
exec("dir 2>&1;", $output) : if on windows
Enjoy
Nitin
----- Original Message -----
From: "Craig Lonsbury" <[EMAIL PROTECTED]>
To: "Bas" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Friday, October 17, 2003 8:40 PM
Subject: RE: [PHP] How can i print out the files in a directory?
> This has been working for me...
> just pass the function the path to the directory you
> want the listing for.
>
> function getDirFiles($dirPath){
> if ($handle = opendir($dirPath)) {
> while (false !== ($file = readdir($handle))) {
> if ($file != "." && $file != "..") {
> $filesArr[] = trim($file);
> }
> }
> closedir($handle);
> }
> return $filesArr;
> }
>
> hth,
> Craig
>
> -----Original Message-----
> From: Bas [mailto:[EMAIL PROTECTED]
> Sent: October 17, 2003 6:42 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP] How can i print out the files in a directory?
>
>
> How can i print out all of the files in a directory?
>
> I want some output as this:
>
> index.php
> login.php
> image1.gif
> image2.jpg
>
>
>
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