you can use simply exec("ls -l 2>&1;", $output) : if on linux OR exec("dir 2>&1;", $output) : if on windows
Enjoy Nitin ----- Original Message ----- From: "Craig Lonsbury" <[EMAIL PROTECTED]> To: "Bas" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Sent: Friday, October 17, 2003 8:40 PM Subject: RE: [PHP] How can i print out the files in a directory? > This has been working for me... > just pass the function the path to the directory you > want the listing for. > > function getDirFiles($dirPath){ > if ($handle = opendir($dirPath)) { > while (false !== ($file = readdir($handle))) { > if ($file != "." && $file != "..") { > $filesArr[] = trim($file); > } > } > closedir($handle); > } > return $filesArr; > } > > hth, > Craig > > -----Original Message----- > From: Bas [mailto:[EMAIL PROTECTED] > Sent: October 17, 2003 6:42 AM > To: [EMAIL PROTECTED] > Subject: [PHP] How can i print out the files in a directory? > > > How can i print out all of the files in a directory? > > I want some output as this: > > index.php > login.php > image1.gif > image2.jpg > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php