hi, when I enter url like that http://localhost/menu.php?status=0 php return an error below : "Warning: Undefined variable: status in D:\calismalar\cengiz_ozdelice\web\menu.php on line 41" my code on 41.line is : if ($status==0) echo '"trying";
what is problem? thank you. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php