hello I'm new with php just learning and i have just a problem with the following code
$dbconnect = mysql_connect("localhost", "prog_tony","PASSWORD"); mysql_select_db("prog_dealer", $dbconnect); $stop = 0; $counter = 1; while(!$stop){ $query = "SELECT name FROM category WHERE id = $counter"; $dbdo = mysql_query($query,$dbconnect); while($row= mysql_fetch_array($dbdo)){ if($row[0]){ $counter++; }else{ $stop=1; } $row[0] = ""; } } I'm getting an error with mysql_fetch_array() which is line 14 because I didn't show the other lines since it is not relevant. here is the error Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/prog/public_html/php/cateadded.php on line 14 Thank you -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php