Thx Erik, it works great except for one detail. It matches numbers too. Can you fix it so it matches only words please ?
For example: $file = 'this is a number 1231 test.'; $words = 'test|number'; Result: [tag]this[/tag] [tag]is[/tag] [tag]a[/tag] [tag]nu[/tag] [sample]number[/sample] [tag]1231[/tag] [sample]test[/sample]. 1231 should stay the same, without tags. thx <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Hello Gregor, > > On 13 Jan 2004 at 15:08, Gregor Jaksa wrote: > > > hello, i need to replace some words in file with [tag]word[/tag] and other > > words with [sample]word[/sample]. > > > > i have a list of words which i need to replace with [sample] tags declared > > like > > $words = 'word1|word2|word3|word4'; > > > > replacing those words is easy i just use preg_replace('/\b( ' . $words . > > ')\b/i', '[sample]$1[/sample]', $file); > > but how to replace all other words that are not in $words array with [tag] > > tag ? > > > > thx in advance! > > Let me see if I understood you correctly: you want to surround all the words in the string > $file that are not also contained in the $words array with [tag] and [/tag]? > > Here's an idea: > > <?php > > $file = 'this is my test string and I just want to use it for a quick test'; > $words = 'test|string'; > > $new_file = preg_replace('/\b('.$words.')\b/', ' [sample]$1[/sample] ', $file); > > $new_file = preg_replace('/\b(?<!\[sample\]|\[)(\w+)(?!\[\/sample\]|\])\b/', > ' [tag]$1[/tag] ', $new_file); > > print $new_file; > > ?> > > Very important: you *must not* forget the spaces before and after the opening and > closing brackets in the replacement string. > > Good luck, > > Erik -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
