From: "Vivian Steller" <[EMAIL PROTECTED]>
> Vivian Steller wrote:
>
> > Hello,
> >
> > as you know there is a new callback function __call($method, $params) in
> > php5. the __call() method of an object is called, if the method named
> > $method is not declared in this class.
> >
> > i want this function simply call the method of another class with
> > "SomeClass::$method(...)" but i'm getting into trouble (bit heavy
> > programming!:) passing the arguments (stored as Array in $params) to the
> > "SomeClass::$method([arguments])" method...
> > further, i think i'm getting problems with objects passed through the
> > __call() method?!
> >
> > any suggestions?
> > thanks
> >
> > vivi
>
> ok, here is an example: hope you'll understand what i want...
>
> <pre>
> <?php
> class MyClass {
> function __call($method, $params) {
> // $params = Array(mixed var, mixed var, ...);
> print("request for " . $method . "()\n");
>
> // how to get objects in this string?!
> // do i have to implement "switch($type) { case
"object": ... }" here?!
> $parameterstring = "\"" . $params[0] . "\"";
> eval("OtherClass::" . $method . "(" .
$parameterstring . ");");
Can't you just say:
OtherClass::$method($params);
here?
>
> }
> }
>
> class OtherClass {
> function OtherMethod($obj = false) {
> if(is_object($obj)) {
> // this method receives an object to show
the difficulties with object
> passed through call...
> if(method_exists($obj, "printSomething"))
{
> $obj->printSomething();
> }
> }
> else {
> print("Error: no object passed! '" . $obj
. "'\n");
> }
> }
> }
>
> class Whatever {
> function printSomething() {
> print("passing object through __call() is
fine\n");
> }
> }
>
> $someObj = new Whatever();
> // $someObj->printSomething();
>
> $MyObj = new MyClass();
> // this works perfectly
> $MyObj->OtherMethod("passing a string");
> // this is my problem...
> $MyObj->OtherMethod($someObj);
> ?>
> </pre>
---John Holmes...
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