Bao or anyone,

Here is my code. $sql works correctly, but am not sure I did this line correct:

$glquery = mysql_query($sql);

because "if ($glquery)" always returns something. I want to know if it returns NULL.

Thanks for your time,
John

-----------snip-----------------

$myconnection = mysql_connect($server,$user,$pass);
mysql_select_db($db,$myconnection);

$eventid = $link_date;
$sql = 'SELECT * FROM '.$table.' where eventid like '.$eventid.';';
#echo $sql;
#SELECT * FROM GMCalendar where eventid like 2004-02-16;
$glquery = mysql_query($sql);

if ($glquery)
{
echo "<td><a href=results.php?eventid=$link_date> $day </a></td>";
}else{
echo "<td> $day </td>";
}

Bao Ruixian wrote:

> John Taylor-Johnston wrote:
> >$sql = 'SELECT * FROM '.$db.'.'.$table.' where eventid like '.$eventid.';';
> >if ($sql ??)
> This will do:
>     if ($sql)

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