Hi,
Friday, March 19, 2004, 12:44:40 AM, you wrote:
F> I would be very interested in a solution to this problem because I have a similar
one.
F> I stored tables on a page.
F> examp:
F> $table_1 = "<table><tr><td>".$name."</td></tr></table>";
F> $table_2 = "<table><tr><td>".$message."</td></tr></table>";
F> etc...
F> and included the page and used the variables (echo $table_1;)
F> The table displayed as it should,
F> however the variables didn't have values( for $name, $message, etc..)
F> I began testing for the problem by defining the string variable
F> for the table on the same page as the php code
F> examp:
F> <?php
F> $table_1 = "<table><tr><td>".$name."</td></tr></table>";
F> $table_2 = "<table><tr><td>".$message."</td></tr></table>";
F> $name = "blah blah";
F> if(blah blah){
F> echo $table_1;}
F> else{
F> echo $table_2;}
?>>
F> Again, the tables printed fine, but the variables ($name, $message) had no values.
F> Most recently, I put the whole dam table in each conditional option.
F> if (blah blah){ echo
F> "<table><tr><td>".$name."</td></tr></table>";}
F> else{ echo "<table><tr><td>".$message."</td></tr></table>";}
F> Voila, the variables have values.
F> It would seem that if a solution was found for Jake's problem
F> it would also solve, or provide a key for solving, this one.
You have to define variable $name before you try to use it.
The only other way would be to eval the string but that is not the way
to go :)
--
regards,
Tom
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