John Nichel wrote: > OOP is not my strong suit, and I'm trying to work with someone > else's code, but am having trouble accessing a value. Let's say I > have an object called $bob, and doing a print_r on $bob produces > this.... > > Array > (
Are you sure $bob is an object? It says above that it's an array. If $bob were an object, print_r() should give "objectname Object" instead of "Array". -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
